Instrument Pilot Courses of Instruction

531

Steve Sconfienza, Ph.D.

Airline Transport Pilot

Flight Instructor: Airplane Single and Multiengine; Instrument Airplane

cell: 518.366.3957

e-mail: docsteve@localnet.com

What is 531 and why is it so important? Well, it is actually 5 **point** 31,
and it just so happens that if you multiply your ground speed (knots)
by 5.31 the result is the vertical speed in feet per minute necessary to hold a
standard three per cent glide slope of an ILS!
For example, at 100 knots, a 3° glide slope requres 531 feet/minute descent rate.

Standard precision instrument approach procedures generally incorporate a three degree descent profile (e.g., an ILS glide slope), although some differ; also, VASI and other approach references are typcially at or near three degrees.

It just so happens that 5.31 is the reduction of three terms based on the trigonometry of an ILS.

- For a right triangle,
- Tangent (angle A) = opposite side / adjacent side
- One nautical mile equals
- 6,076.11549 feet (let's just say 6076.12)
- One hour (as in knots) equals
- 60 minutes (as in feet per minute)
- In the ILS,
- opposite side is vertical speed
- adjacent side is ground speed

To solve the triangle, first convert to common units. To convert knots (ground speed) to fpm (vertical speed) do the following:

- knots * 6076.12 = feet per hour
- feet per hour / 60 = feet per minute

Then to solve the triangle (now that all terms are in the same units, fpm) do the following:

- tan 3° = vertical speed (fpm) / ground speed (fpm)

Which rearranges to

- tan 3° * ground speed (fpm) = vertical speed (fpm)

Where tan 3° = 0.052408 (from any slide rule, trig table, or — even — a computer!).

But this can be reduced to one step, given the three constant terms will always be there: tan 3°, knots to fpm conversion factor, and –per hour to –per minute conversion factor. So this reduces to the following:

- 0.052408 = [vs] fpm / [gs] knots
- 0.052408 = [vs] fpm / ([gs] knots * 6076.12)
- 0.052408 = [vs] fpm / ([gs] knots * (6076.12/60))
- 0.052408 = [vs] fpm / ([gs] knots * 101.269)

At this point, move the ground speed to the left of the equal sign by multiplying both sides of the equal sign by the quantity ([gs] knots * 101.269), which gives...

- ([gs] knots * 101.269) * 0.052408 = [vs] fpm
- [gs] knots * 101.269 * 0.052408 = [vs] fpm
- [gs] knots * 5.3073 = [vs] fpm

Which rounds to [gs] knots * 5.31 = [vs] fpm

I am So Cool!

While most glideslopes in the United States are three degrees; however, this is not a standard that is cast in stone. Yes, there are those odd ones out there, typically, in the range down to 2.5 degrees or up to 3.1 degrees, so it's best to be prepared before your heading down the ILS.

The United States Standard for Terminal Instrument Procedures TERPS, Third Edition [8260.3B]) provides information concerning the maximum authorized glide slope angles by aricraft categories. (The arcraft categories are defined in 14 CFR 97 and are based on the aricraft's computed indicated approach speed [1.3 Vso] at the maximum certificated landing weight.) Glide slope angles above three degrees require the approval of the the FAA's Flight Standards Service (or relevant military authority).

- Category A:Speed (1.3 Vso) less than 91 knots.
- Category B:Speed (1.3 Vso) 91 knots or more but less than 121 knots.
- Category C:Speed (1.3 Vso) 121 knots or more but less than 141 knots.
- Category D:Speed (1.3 Vso) 141 knots or more but less than 166 knots.
- Category E:Speed (1.3 Vso) 166 knots or more.

Aircraft Category | Maximum Glidepath Angle | ||
---|---|---|---|

A | 1.3 Vso | 80 knots or less | 6.4 |

81 to 90 knots | 5.7 | ||

B | 4.2 | ||

C | 3.6 | ||

D | 3.1 | ||

E | 3.1 |

N.B. You can come down the approach course at any speed you want
(i.e., V_{REF} as chosen by **you**):
the official "approach category" for the aircraft is based only on 1.3
V_{SO},
the aricraft's computed indicated approach speed at the maximum certificated landing weight.

A table of descent rate conversions besides 5.31 is available for the curious, obsessive, or those that happen to be flying such a glide slope:

As an aide in computing approach descent rates versus groundspeed, this table provides knots-to-fpm conversions for the full range of authorized glide slope angles.

This interactive spreadsheet computes descent rates (in fpm) per groundspeed (in knots) based on the descent profile (including non-standard glide-slope angles).

- [ Approach/Descent rates worksheet ] (In MS-Excel format) [size: 71.680 kb]

There are two interactive worksheets in the file:

- "Specified Airspeeds" simply computes the required descent rate based on glide slope angle and groundspeed;
- "Selected Airspeeds" generates a table of descent rates by ground speeds for given glide slope angles.

Setting it at three degrees generates a reference for descent rates by speed for a standard ILS. For flight planning purposes, the second worksheet is configured to print on a single page for in-flight reference (but do a "print preview" and check the settings on your own printer).

You may have noticed that the topology of the ILS is always going to be a right triangle, with the three legs being ground speed, vertical speed, and airspeed, and no, airspeed cannot be identical to ground speed in still air: the vertical component absorbs some amount of the travel (the airspeed), thus in still air the ground speed will be lower than the airspeed. How much? Well, not a whole lot, not worth the effor to compute, but just so that you know, assume a 100 knot groundspeed for the following (e.g., as read from an ILS-DME):

- Airspeed, vertical speed, and ground speed make up a right triangle, with [see diagram above]
- Airspeed: hypotenuse of the triangle
- Ground speed: one leg adjoining the right angle
- Vertical speed: sedonc leg adjoining the right angle

- Solving a right triangle:
- the hypotenuse is side c, with sides a and b the sides bordering the right angle.
- c
^{2}= a^{2}+ b^{2}- let a = Vertical speed:
**531 feet per minute** - let b = Ground speed: 100 knots = 607,612 feet per hour =
**10,127 feet per minute** - let c = Airspeed:
- c
^{2}= 531^{2}+ 10,127^{2} - c
^{2}= 281,961 + 102,553,276 - c
^{2}= 102,835,237 - c = √102,835,237
- c = 10,141 feet per minute
[times 60 minutes per hour divided by 6,076.12 feet per mile . . .]

- Airspeed = 100.13 knots!

- c

- let a = Vertical speed:

The website "Flightinfo.com" has various rules of thumb related to ILS approaches.

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rev. 7 December 2012

Copyright © 2012

Steve Sconfienza, Ph.D.

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